San Felipe Pueblo (Eastern Keres: Katishtya, Navajo Tsédááʼkin) is a census-designated place (CDP) in Sandoval County, New Mexico, United States, and is located 10 miles (16 km) north of Bernalillo. As of the 2000 census, the CDP population was 2,080. It is part of the Albuquerque Metropolitan Statistical Area.
| Name: | San Felipe Pueblo CDP |
|---|---|
| LSAD Code: | 57 |
| LSAD Description: | CDP (suffix) |
| State: | New Mexico |
| County: | Sandoval County |
| Elevation: | 5,131 ft (1,564 m) |
| Total Area: | 12.26 sq mi (31.76 km²) |
| Land Area: | 11.98 sq mi (31.04 km²) |
| Water Area: | 0.28 sq mi (0.73 km²) |
| Total Population: | 2,542 |
| Population Density: | 212.13/sq mi (81.91/km²) |
| Area code: | 505 |
| FIPS code: | 3567450 |
| GNISfeature ID: | 0928802 |
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San Felipe Pueblo location map. Where is San Felipe Pueblo CDP?
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Geography
San Felipe Pueblo is located at 35°25′37″N 106°26′37″W / 35.42694°N 106.44361°W / 35.42694; -106.44361 (35.426985, -106.443593).
According to the United States Census Bureau, the CDP has a total area of 12.2 square miles (31.6 km), of which 11.9 square miles (30.8 km) is land and 0.3 square mile (0.8 km) (2.46%) is water.
See also
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