Map of Palmyra CDP, Utah

Palmyra is a census-designated place (CDP) in Utah County, Utah, United States. It is part of the Provo–Orem Metropolitan Statistical Area. The population was 491 at the 2010 census. Palmyra is located directly west of Springville and northwest of Spanish Fork.

Palmyra was first settled in 1852.

Palmyra CDP overview:
Name:	Palmyra CDP
LSAD Code:	57
LSAD Description:	CDP (suffix)
State:	Utah
County:	Utah County
Elevation:	4,524 ft (1,379 m)
Total Area:	11.7 sq mi (30.4 km²)
Land Area:	11.5 sq mi (29.8 km²)
Water Area:	0.2 sq mi (0.6 km²)
Total Population:	491
Population Density:	42/sq mi (16/km²)
ZIP code:	84660
Area code:	801
FIPS code:	4957630
GNISfeature ID:	1444167

Online Interactive Map

Palmyra online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Palmyra location map. Where is Palmyra CDP?

Palmyra location on the U.S. Map. Where is Palmyra CDP. — Palmyra location on the U.S. Map.

Palmyra location on the Utah map. Where is Palmyra CDP. — Location of Palmyra in Utah.

History

Palmyra, located seven miles south of Provo, was founded on the Spanish Fork River in 1852. In March 1853, Stephen Markham was ordained a bishop and set apart to preside over the Palmyra LDS Ward. The town was eventually abandoned sometime in 1856, under the advice of Brigham Young. Most of the settlers located farther up the river, where the site of present-day Spanish Fork had been chosen and where a survey of a city had already been made. At the turn of the century, the area was resettled.

Palmyra Road Map

Palmyra city Satellite Map

Geography

According to the United States Census Bureau, the CDP has a total area of 11.7 square miles (30.4 km), of which 11.5 square miles (29.8 km) is land and 0.23 square miles (0.6 km), or 2.05%, is water.