Map of De Soto village, Wisconsin

De Soto is a village mostly in Vernon County but also in Crawford County in Wisconsin. The population was 287 at the 2010 census. Of this, 179 were in living in Vernon County, and 108 were living in Crawford County. The downtown and business area is located in Crawford County.

De Soto village overview:
Name:	De Soto village
LSAD Code:	47
LSAD Description:	village (suffix)
State:	Wisconsin
County:	Crawford County, Vernon County
Elevation:	653 ft (199 m)
Total Area:	1.25 sq mi (3.24 km²)
Land Area:	1.22 sq mi (3.16 km²)
Water Area:	0.03 sq mi (0.08 km²)
Total Population:	287
Population Density:	228.31/sq mi (88.16/km²)
Area code:	608
FIPS code:	5519850
GNISfeature ID:	1563761
Website:	www.desotowi.com

Online Interactive Map

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De Soto online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

De Soto location map. Where is De Soto village?

De Soto location on the U.S. Map. Where is De Soto village. — De Soto location on the U.S. Map.

De Soto location on the Wisconsin map. Where is De Soto village. — Location of De Soto in Wisconsin.

History

De Soto was named after Hernando De Soto the explorer who discovered the Mississippi.

De Soto Road Map

De Soto city Satellite Map

Geography

De Soto is located at 43°25′37″N 91°11′49″W / 43.42694°N 91.19694°W / 43.42694; -91.19694 (43.426905, -91.196841).

According to the United States Census Bureau, the village has a total area of 1.34 square miles (3.47 km), of which, 1.25 square miles (3.24 km) of it is land and 0.09 square miles (0.23 km) is water.