De Soto is a village mostly in Vernon County but also in Crawford County in Wisconsin. The population was 287 at the 2010 census. Of this, 179 were in living in Vernon County, and 108 were living in Crawford County. The downtown and business area is located in Crawford County.
| Name: | De Soto village |
|---|---|
| LSAD Code: | 47 |
| LSAD Description: | village (suffix) |
| State: | Wisconsin |
| County: | Crawford County, Vernon County |
| Elevation: | 653 ft (199 m) |
| Total Area: | 1.25 sq mi (3.24 km²) |
| Land Area: | 1.22 sq mi (3.16 km²) |
| Water Area: | 0.03 sq mi (0.08 km²) |
| Total Population: | 287 |
| Population Density: | 228.31/sq mi (88.16/km²) |
| Area code: | 608 |
| FIPS code: | 5519850 |
| GNISfeature ID: | 1563761 |
| Website: | www.desotowi.com |
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De Soto location map. Where is De Soto village?
History
De Soto was named after Hernando De Soto the explorer who discovered the Mississippi.
De Soto Road Map
De Soto city Satellite Map
Geography
De Soto is located at 43°25′37″N 91°11′49″W / 43.42694°N 91.19694°W / 43.42694; -91.19694 (43.426905, -91.196841).
According to the United States Census Bureau, the village has a total area of 1.34 square miles (3.47 km), of which, 1.25 square miles (3.24 km) of it is land and 0.09 square miles (0.23 km) is water.
See also
Map of Wisconsin State and its subdivision:- Adams
- Ashland
- Barron
- Bayfield
- Brown
- Buffalo
- Burnett
- Calumet
- Chippewa
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- Columbia
- Crawford
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