Lake Harbor is a census-designated place (CDP) in Palm Beach County, Florida, United States. The population was 49 at the 2020 census. It located along the southern banks of Lake Okeechobee, at the beginning of the Miami Canal. John Stretch Park is also located alongside the north end of Lake Harbor and the lake.
Name: | Lake Harbor CDP |
---|---|
LSAD Code: | 57 |
LSAD Description: | CDP (suffix) |
State: | Florida |
County: | Palm Beach County |
Elevation: | 13 ft (4 m) |
Total Area: | 1.32 sq mi (3.42 km²) |
Land Area: | 1.32 sq mi (3.42 km²) |
Water Area: | 0.00 sq mi (0.00 km²) |
Total Population: | 49 |
Population Density: | 37.09/sq mi (14.33/km²) |
ZIP code: | 33459 |
Area code: | 561 |
FIPS code: | 1238000 |
GNISfeature ID: | 0285247 |
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Lake Harbor location map. Where is Lake Harbor CDP?
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Geography
Lake Harbor is located at 26°41′13″N 80°48′27″W / 26.68694°N 80.80750°W / 26.68694; -80.80750 (26.686985, -80.807613).
According to the United States Census Bureau, the CDP has a total area of 3.4 km (1.3 mi), all land. The community is centered at the intersection of Mutt-Thomas road and U.S. Route 27 (which runs concurrently with Florida State Road 80).
See also
Map of Florida State and its subdivision:- Alachua
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