Map of Allen village, Nebraska

Allen is a village in Dixon County, Nebraska, United States. Located south of US Hwy 20 on NE Hwy 9 between Martinsburg, NE and Wakefield, NE. It is part of the Sioux City, IA–NE–SD Metropolitan Statistical Area. The population was 377 at the 2010 census.

Allen village overview:
Name:Allen village
LSAD Code:47
LSAD Description:village (suffix)
State:Nebraska
County:Dixon County
Elevation:1,529 ft (466 m)
Total Area:0.37 sq mi (0.96 km²)
Land Area:0.37 sq mi (0.96 km²)
Water Area:0.00 sq mi (0.00 km²)
Total Population:355
Population Density:954.30/sq mi (368.28/km²)
ZIP code:68710
Area code:402
FIPS code:3100870
GNISfeature ID:0826959

Online Interactive Map

Allen online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Allen location map. Where is Allen village?

Allen location on the U.S. Map. Where is Allen village.
Allen location on the U.S. Map.
Allen location on the Nebraska map. Where is Allen village.
Location of Allen in Nebraska.

History

Allen was established in 1890 when the railroad was extended to that point. It was named for Henry Allen, the original owner of the town site. Allen was incorporated as a village in 1893.

Allen Road Map

Road map of Allen
Road map of Allen

Allen city Satellite Map

Satellite map of Allen
Satellite map of Allen

Geography

Allen is located at 42°24′56″N 96°50′41″W / 42.41556°N 96.84472°W / 42.41556; -96.84472 (42.415674, -96.844587).

According to the United States Census Bureau, the village has a total area of 0.37 square miles (0.96 km), all land.

See also

Map of Nebraska State and its subdivision: Map of other states:
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