Map of Irondale village, Ohio

Irondale is a village in northern Jefferson County, Ohio, United States. The population was 326 at the 2020 census. It is part of the Weirton–Steubenville metropolitan area.

Irondale village overview:
Name:Irondale village
LSAD Code:47
LSAD Description:village (suffix)
State:Ohio
County:Jefferson County
Elevation:709 ft (216 m)
Total Area:1.48 sq mi (3.82 km²)
Land Area:1.45 sq mi (3.75 km²)
Water Area:0.03 sq mi (0.07 km²)
Total Population:326
Population Density:224.98/sq mi (86.85/km²)
ZIP code:43932
Area code:330
FIPS code:3937422
GNISfeature ID:1064888

Online Interactive Map

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Irondale online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Irondale location map. Where is Irondale village?

Irondale location on the U.S. Map. Where is Irondale village.
Irondale location on the U.S. Map.
Irondale location on the Ohio map. Where is Irondale village.
Location of Irondale in Ohio.

History

Irondale was originally known as Pottsdale, for Samuel Potts, who started a salt operation at Yellow Creek circa 1806. In 1869 Morgan & Hunter laid out the original plat of what was then called Hunterville which later was changed to Irondale after the discovery of iron ore and other minerals used in the manufacture of tin. Coal mining began at the settlement in 1861. A blast furnace was built later to supply iron to the tin mill which gave the town its new name, Irondale. The first commercially successful tin mill in the United States operated in Irondale in the 1880s.

Former Irondale Mayor Bill “Red” Allen recently made history by losing two separate elections in less than 365 days to two separate people, confirming the end of the Allen family political dynasty in the town which lasted over 30 years.

Irondale Road Map

Road map of Irondale
Road map of Irondale

Irondale city Satellite Map

Satellite map of Irondale
Satellite map of Irondale

Geography

Irondale is located at 40°34′14″N 80°43′37″W / 40.57056°N 80.72694°W / 40.57056; -80.72694 (40.570621, -80.726993).

According to the United States Census Bureau, the village has a total area of 1.48 square miles (3.83 km), of which 1.45 square miles (3.76 km) is land and 0.03 square miles (0.08 km) is water.

See also

Map of Ohio State and its subdivision: Map of other states:
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Parent Unit Map

Map of Jefferson County, Ohio
Jefferson County is a county located in the U.S. state of Ohio. As of the 2020 census, the population was 65,249. Its county seat is Steubenville. The county is named for Thomas Jefferson, who was vice president at the time of its creation. Jefferson County is part of the Weirton–Steubenville, WV–OH Metropolitan Statistical Area, which ... Read more
Map of Jefferson County, Ohio

Related Administrative Divisions