Map of Linndale village

Linndale is the smallest village in Cuyahoga County, Ohio, United States. It is landlocked, surrounded by the city of Cleveland and the suburb of Brooklyn. According to the 2020 census, the population was 108.

Linndale village overview:
Name:	Linndale village
LSAD Code:	47
LSAD Description:	village (suffix)
State:	Ohio
County:	Cuyahoga County
Elevation:	755 ft (230 m)
Total Area:	0.07 sq mi (0.19 km²)
Land Area:	0.07 sq mi (0.19 km²)
Water Area:	0.00 sq mi (0.00 km²)
Total Population:	108
Population Density:	1,479.45/sq mi (573.54/km²)
ZIP code:	44135
Area code:	216
FIPS code:	3943918
GNISfeature ID:	1065002
Website:	www.linndalevillage-oh.gov

Online Interactive Map

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Linndale online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Linndale location map. Where is Linndale village?

Linndale location on the U.S. Map. Where is Linndale village. — Linndale location on the U.S. Map.

Linndale location on the Ohio map. Where is Linndale village. — Location of Linndale in Ohio.

Linndale Road Map

Linndale city Satellite Map

Geography

Linndale is located at 41°26′39″N 81°46′3″W / 41.44417°N 81.76750°W / 41.44417; -81.76750 (41.444050, -81.767476).

According to the United States Census Bureau, the village has a total area of 0.08 square miles (0.21 km), all land. The southeast border is along the municipal limits of Brooklyn; the remainder of Linndale is surrounded by Cleveland, specifically the neighborhoods of West Boulevard, Jefferson, and Bellaire–Puritas.