Map of Warrensville Heights city

Warrensville Heights is a city located in Cuyahoga County, Ohio, United States. It is an East Side suburb of Cleveland. The population was 13,789 at the 2020 U.S. Census.

Warrensville Heights city overview:
Name:	Warrensville Heights city
LSAD Code:	25
LSAD Description:	city (suffix)
State:	Ohio
County:	Cuyahoga County
Incorporated:	1960
Elevation:	1,037 ft (316 m)
Total Area:	4.13 sq mi (10.69 km²)
Land Area:	4.12 sq mi (10.68 km²)
Water Area:	0.01 sq mi (0.01 km²) 0.24%
Total Population:	13,789
Population Density:	3,344.41/sq mi (1,291.27/km²)
Area code:	216
FIPS code:	3980990
GNISfeature ID:	1047579
Website:	www.cityofwarrensville.com

Online Interactive Map

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Warrensville Heights online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Warrensville Heights location map. Where is Warrensville Heights city?

Warrensville Heights location on the U.S. Map. Where is Warrensville Heights city. — Warrensville Heights location on the U.S. Map.

Warrensville Heights location on the Ohio map. Where is Warrensville Heights city. — Location of Warrensville Heights in Ohio.

Warrensville Heights Road Map

Warrensville Heights city Satellite Map

Geography

Warrensville Heights is located at 41°26′19″N 81°31′24″W / 41.43861°N 81.52333°W / 41.43861; -81.52333 (41.438653, -81.523262).

According to the United States Census Bureau, the city has a total area of 4.14 square miles (10.72 km), of which 4.13 square miles (10.70 km) is land and 0.01 square miles (0.03 km) is water.