Map of Nevada village, Ohio

Nevada (/nəˈveɪdə/ nə-VAY-də) is a village in Wyandot County, Ohio, United States. The population was 760 at the 2010 census.

Nevada village overview:
Name:Nevada village
LSAD Code:47
LSAD Description:village (suffix)
State:Ohio
County:Wyandot County
Elevation:928 ft (283 m)
Total Area:1.03 sq mi (2.66 km²)
Land Area:1.03 sq mi (2.66 km²)
Water Area:0.00 sq mi (0.00 km²)
Total Population:706
Population Density:688.11/sq mi (265.72/km²)
ZIP code:44849
Area code:740
FIPS code:3953942
GNISfeature ID:1056444

Online Interactive Map

Nevada online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Nevada location map. Where is Nevada village?

Nevada location on the U.S. Map. Where is Nevada village.
Nevada location on the U.S. Map.
Nevada location on the Ohio map. Where is Nevada village.
Location of Nevada in Ohio.

History

Nevada was laid out in 1852, and named after the Sierra Nevada. A post office called Nevada has been in operation since 1854.

Nevada Road Map

Road map of Nevada
Road map of Nevada

Nevada city Satellite Map

Satellite map of Nevada
Satellite map of Nevada

Geography

Nevada is located at 40°49′1″N 83°7′54″W / 40.81694°N 83.13167°W / 40.81694; -83.13167 (40.816867, -83.131664).

According to the United States Census Bureau, the village has a total area of 1.03 square miles (2.67 km), all land.

See also

Map of Ohio State and its subdivision: Map of other states:
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