Map of Port Jefferson village, Ohio

Port Jefferson is a village in Salem Township, Shelby County, Ohio, United States. The population was 371 at the 2010 census.

Port Jefferson village overview:
Name:	Port Jefferson village
LSAD Code:	47
LSAD Description:	village (suffix)
State:	Ohio
County:	Shelby County
Elevation:	971 ft (296 m)
Total Area:	0.15 sq mi (0.40 km²)
Land Area:	0.15 sq mi (0.39 km²)
Water Area:	0.00 sq mi (0.00 km²)
Total Population:	308
Population Density:	2,026.32/sq mi (780.00/km²)
ZIP code:	45360
Area code:	937, 326
FIPS code:	3964262
GNISfeature ID:	1061565

Online Interactive Map

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Port Jefferson online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Port Jefferson location map. Where is Port Jefferson village?

Port Jefferson location on the U.S. Map. Where is Port Jefferson village. — Port Jefferson location on the U.S. Map.

Port Jefferson location on the Ohio map. Where is Port Jefferson village. — Location of Port Jefferson in Ohio.

History

Port Jefferson had its start around the time the Miami and Erie Canal was extended to that point. The town site was platted in 1836. The village was incorporated in 1842.

Port Jefferson Road Map

Port Jefferson city Satellite Map

Geography

Port Jefferson is located at 40°19′50″N 84°05′28″W / 40.330423°N 84.090979°W / 40.330423; -84.090979.

According to the United States Census Bureau, the village has a total area of 0.19 square miles (0.49 km), of which 0.17 square miles (0.44 km) is land and 0.02 square miles (0.05 km) is water.