Map of Salineville village

Salineville (/səˈliːnvɪl/ sə-LEEN-vil ) is a village in southwestern Columbiana County, Ohio, United States. The population was 1,206 at the 2020 census. It is part of the Salem micropolitan area, about 20 miles (32 km) northwest of Steubenville and 34 miles (55 km) southwest of Youngstown.

Salineville village overview:
Name:	Salineville village
LSAD Code:	47
LSAD Description:	village (suffix)
State:	Ohio
County:	Columbiana County
Elevation:	899 ft (274 m)
Total Area:	2.21 sq mi (5.72 km²)
Land Area:	2.21 sq mi (5.72 km²)
Water Area:	0.00 sq mi (0.00 km²)
Total Population:	1,206
Population Density:	545.95/sq mi (210.77/km²)
ZIP code:	43945
Area code:	330, 234
FIPS code:	3970100
GNISfeature ID:	1065281

Online Interactive Map

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Salineville online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Salineville location map. Where is Salineville village?

Salineville location on the U.S. Map. Where is Salineville village. — Salineville location on the U.S. Map.

Salineville location on the Ohio map. Where is Salineville village. — Location of Salineville in Ohio.

History

Salineville was laid out in 1839 and incorporated as a village in 1848. Salineville was named from the salt deposits (salinity) found on Yellow Creek.

The Civil War Battle of Salineville, which ended Morgan’s Raid and resulted in the capture of Confederate General John Hunt Morgan, took place near Salineville on July 26, 1863.