Gibson is a city in Keokuk County, Iowa, United States. The population was 63 at the time of the 2020 census.
| Name: | Gibson city |
|---|---|
| LSAD Code: | 25 |
| LSAD Description: | city (suffix) |
| State: | Iowa |
| County: | Keokuk County |
| Elevation: | 896 ft (273 m) |
| Total Area: | 0.06 sq mi (0.16 km²) |
| Land Area: | 0.06 sq mi (0.16 km²) |
| Water Area: | 0.00 sq mi (0.00 km²) |
| Total Population: | 63 |
| Population Density: | 1,000.00/sq mi (385.38/km²) |
| ZIP code: | 50104 |
| Area code: | 641 |
| FIPS code: | 1930540 |
| GNISfeature ID: | 0456895 |
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Geography
Gibson is located at 41°28′50″N 92°23′35″W / 41.48056°N 92.39306°W / 41.48056; -92.39306 (41.480571, -92.393031).
According to the United States Census Bureau, the city has a total area of 0.07 square miles (0.18 km), all of it land.
See also
Map of Iowa State and its subdivision:- Adair
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