Hayesville is a city in Keokuk County, Iowa, United States. The population was 41 at the time of the 2020 census.
| Name: | Hayesville city |
|---|---|
| LSAD Code: | 25 |
| LSAD Description: | city (suffix) |
| State: | Iowa |
| County: | Keokuk County |
| Elevation: | 797 ft (243 m) |
| Total Area: | 0.25 sq mi (0.65 km²) |
| Land Area: | 0.25 sq mi (0.65 km²) |
| Water Area: | 0.00 sq mi (0.00 km²) |
| Total Population: | 41 |
| Population Density: | 164.00/sq mi (63.31/km²) |
| ZIP code: | 52562 |
| Area code: | 641 |
| FIPS code: | 1935445 |
| GNISfeature ID: | 0457351 |
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Geography
Hayesville is located at 41°15′52″N 92°14′56″W / 41.264570°N 92.248880°W / 41.264570; -92.248880 (41.264570, -92.248880).
According to the United States Census Bureau, the city has a total area of 0.25 square miles (0.65 km), all of it land.
See also
Map of Iowa State and its subdivision:- Adair
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