Map of Jacksonville CDP, Iowa

Jacksonville is an unincorporated community and census-designated place in Jackson Township, Shelby County, Iowa, in the United States. As of the 2010 Census the population of Jacksonville was 30.

Jacksonville CDP overview:
Name:Jacksonville CDP
LSAD Code:57
LSAD Description:CDP (suffix)
State:Iowa
County:Shelby County
Elevation:1,276 ft (389 m)
Total Area:0.10 sq mi (0.25 km²)
Land Area:0.10 sq mi (0.25 km²)
Water Area:0.00 sq mi (0.00 km²)
Total Population:29
Population Density:295.92/sq mi (113.85/km²)
Area code:712
FIPS code:1939180
GNISfeature ID:457904

Online Interactive Map

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Jacksonville online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Jacksonville location map. Where is Jacksonville CDP?

Jacksonville location on the U.S. Map. Where is Jacksonville CDP.
Jacksonville location on the U.S. Map.
Jacksonville location on the Iowa map. Where is Jacksonville CDP.
Location of Jacksonville in Iowa.

History

Jacksonville was originally built up chiefly by the Danish. Jacksonville’s population was 12 in 1902, and 75 in 1925.

Jacksonville Road Map

Road map of Jacksonville
Road map of Jacksonville

Jacksonville city Satellite Map

Satellite map of Jacksonville
Satellite map of Jacksonville

See also

Map of Iowa State and its subdivision: Map of other states:
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Parent Unit Map

Map of Shelby County, Iowa
Shelby County is a county located in the U.S. state of Iowa. As of the 2020 census, the population was 11,746. The county seat is Harlan. Its name is in honor of Isaac Shelby, the first Governor of Kentucky. Shelby County overview: Name: Shelby County FIPS code: 19-165 State: Iowa Founded: 1851 Named for: Isaac ... Read more
Map of Shelby County, Iowa

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