Sexton is an unincorporated community and census-designated place in Irvington Township, Kossuth County, Iowa, United States. It is located at the intersection of U.S. Route 18 and Kossuth CR P60. As of the 2010 census it had a population of 37.
Name: | Sexton CDP |
---|---|
LSAD Code: | 57 |
LSAD Description: | CDP (suffix) |
State: | Iowa |
County: | Kossuth County |
Elevation: | 1,220 ft (370 m) |
Total Area: | 2.20 sq mi (5.70 km²) |
Land Area: | 2.20 sq mi (5.70 km²) |
Water Area: | 0.00 sq mi (0.00 km²) |
Total Population: | 46 |
Population Density: | 20.89/sq mi (8.07/km²) |
ZIP code: | 50483 |
Area code: | 515 |
FIPS code: | 1971715 |
GNISfeature ID: | 461516 |
Online Interactive Map
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Sexton location map. Where is Sexton CDP?
History
Sexton was platted in 1889. Sexton’s population was 42 in 1902.
The town contained a post office from August 1888 until May 1974.
A few houses, a Racer’s Bar and Grill and the Sexton elevator remain.
Sexton Road Map
Sexton city Satellite Map
Geography
Sexton is in southeastern Kossuth County, 8 miles (13 km) east of Algona, the county seat, and 5 miles (8 km) west of Wesley. According to the U.S. Census Bureau, the Sexton CDP has an area of 2.2 square miles (5.7 km), all land. The CDP is on the south side of U.S. Route 18.
See also
Map of Iowa State and its subdivision:- Adair
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