Map of Searsboro city

Searsboro in an unincorporated community in Poweshiek County, Iowa, United States. The population was 148 at the 2010 census. The city attempted to disincorporate in 2011, but the move failed when Poweshiek County refused to take control of the city’s infrastructure.

Searsboro city overview:
Name:Searsboro city
LSAD Code:25
LSAD Description:city (suffix)
State:Iowa
County:Poweshiek County
Elevation:843 ft (257 m)
Total Area:0.45 sq mi (1.17 km²)
Land Area:0.45 sq mi (1.17 km²)
Water Area:0.00 sq mi (0.00 km²)
Total Population:129
Population Density:286.03/sq mi (110.51/km²)
ZIP code:50242
Area code:641
FIPS code:1971355
GNISfeature ID:0461495

Online Interactive Map

Searsboro online map. Source: Basemap layers from Google Map, Open Street Map (OSM), Arcgisonline, Wmflabs. Boundary Data from Database of Global Administrative Areas.

Searsboro location map. Where is Searsboro city?

Searsboro location on the U.S. Map. Where is Searsboro city.
Searsboro location on the U.S. Map.
Searsboro location on the Iowa map. Where is Searsboro city.
Location of Searsboro in Iowa.

Searsboro Road Map

Road map of Searsboro
Road map of Searsboro

Searsboro city Satellite Map

Satellite map of Searsboro
Satellite map of Searsboro

Geography

Searsboro is located at 41°34′46″N 92°42′13″W / 41.57944°N 92.70361°W / 41.57944; -92.70361 (41.579519, -92.703703).

According to the United States Census Bureau, the city has a total area of 0.45 square miles (1.17 km), all land.

See also

Map of Iowa State and its subdivision: Map of other states:
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