Searsboro in an unincorporated community in Poweshiek County, Iowa, United States. The population was 148 at the 2010 census. The city attempted to disincorporate in 2011, but the move failed when Poweshiek County refused to take control of the city’s infrastructure.
| Name: | Searsboro city |
|---|---|
| LSAD Code: | 25 |
| LSAD Description: | city (suffix) |
| State: | Iowa |
| County: | Poweshiek County |
| Elevation: | 843 ft (257 m) |
| Total Area: | 0.45 sq mi (1.17 km²) |
| Land Area: | 0.45 sq mi (1.17 km²) |
| Water Area: | 0.00 sq mi (0.00 km²) |
| Total Population: | 129 |
| Population Density: | 286.03/sq mi (110.51/km²) |
| ZIP code: | 50242 |
| Area code: | 641 |
| FIPS code: | 1971355 |
| GNISfeature ID: | 0461495 |
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Geography
Searsboro is located at 41°34′46″N 92°42′13″W / 41.57944°N 92.70361°W / 41.57944; -92.70361 (41.579519, -92.703703).
According to the United States Census Bureau, the city has a total area of 0.45 square miles (1.17 km), all land.
See also
Map of Iowa State and its subdivision:- Adair
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